(4y^2-2y+4)-(5y^2-2y+3)=

Solution for (4y^2-2y+4)-(5y^2-2y+3)= equation:

Simplifying
(4y2 + -2y + 4) + -1(5y2 + -2y + 3) = 0

Reorder the terms:
(4 + -2y + 4y2) + -1(5y2 + -2y + 3) = 0

Remove parenthesis around (4 + -2y + 4y2)
4 + -2y + 4y2 + -1(5y2 + -2y + 3) = 0

Reorder the terms:
4 + -2y + 4y2 + -1(3 + -2y + 5y2) = 0
4 + -2y + 4y2 + (3 * -1 + -2y * -1 + 5y2 * -1) = 0
4 + -2y + 4y2 + (-3 + 2y + -5y2) = 0

Reorder the terms:
4 + -3 + -2y + 2y + 4y2 + -5y2 = 0

Combine like terms: 4 + -3 = 1
1 + -2y + 2y + 4y2 + -5y2 = 0

Combine like terms: -2y + 2y = 0
1 + 0 + 4y2 + -5y2 = 0
1 + 4y2 + -5y2 = 0

Combine like terms: 4y2 + -5y2 = -1y2
1 + -1y2 = 0

Solving
1 + -1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y2 = 0 + -1
-1y2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1y2 = -1

Divide each side by '-1'.
y2 = 1

Simplifying
y2 = 1

Take the square root of each side:
y = {-1, 1}